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Content about : Hibernate mapping Class
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This is First Class for this Project : My Spring J2EE Solution With Hibernate
This class mapping to table Example you can download sql script on download page

Example Source Code

package com.en.hibernate;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

/**
* @author Somsuksri Kasemsuk
* @since  13-08-2009
*/

@Entity
@Table(name = “example”)
public class Example implements java.io.Serializable {
private static final long serialVersionUID = -169364292963401081L;

@Id
@Column(name = “code_id”)
private Integer codeId;

@Column(name = “tdesc”)
private String tdesc;

@Column(name = “edesc”)
private String edesc;

public Integer getCodeId() {
return codeId;
}

public void setCodeId(Integer codeId) {
this.codeId = codeId;
}

public String getTdesc() {
return tdesc;
}

public void setTdesc(String tdesc) {
this.tdesc = tdesc;
}

public String getEdesc() {
return edesc;
}

public void setEdesc(String edesc) {
this.edesc = edesc;
}
}

Development Hibernate, hibernate-trigger, Spring Hibernate

Hibernate Criteria Query
Content about :Hibernate Criteria Query
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You can add condition to Criteria with Example Code
List objList = session.createCriteria(MyMappingClass.class)
.add( Restrictions.like(”fname1″, “some data%”) )
.add( Restrictions.or(
Restrictions.eq( “fname2″, “some data” ),
Restrictions.isNull(”fname3″)
) ).list();
Note: You Can add many of Restrictions for One Criteria

Development criteria-query, Hibernate

Content about :Hibernate Criteria Using Criteria
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Hibernate Criteria
You  can create Criteria with Example Code

Criteria ctr = sessiong.createCriteria(MyMappingClass.class);
List myObj = ctr.list();

With this code you will get List off Data from Mapping Table in Mapping Class

Development criteria-query, Hibernate, oracle